Show the calculation of the expected velocity at the bottom of hill 1 if friction is zero and g=9.8m/s/s (Remember to include the formula, show substitutions and include units at all steps. Top of hill #1=.8m(80cm)
bottom of hill#1=0m(0cm)
How would I calcualte this please help, will mark the brainliest

2b2t

explanation:

2b2t

the old price per ounce is c/4.

the new price per ounce is c/3.6.

the ratio of the old price to the new one is

(c/4)/(c/3.6) = (c/c)×(3.6/4) = 0.9 . . = 9/10 . . "nine tenths" in either form

i dont have a visual in front of me, but i can you reason to try to get the right one. the graph should look like this, 0 to 6 there is a spike, 12 to 14 there should be a very low point. slight increase in the graph at 12 to 14, and flat 14 to 18

explanation: