A car traveling at 25 meters per second is brought to stop by a force over a 10 second timer interval. What was the acceleration of the car during the 10 second time interval.

–2.5 m/s²

Explanation:

From the question given above, the following data were obtained:

Initial velocity (u) = 25 m/s

Final velocity (v) = 0 m/s

Time (t) = 10 s

Acceleration (a) =?

Acceleration can simply be defined as the rate of change of velocity with time. Mathematically, it can be expressed as:

a = (v – u) /t

Where:

a => is the acceleration

v => is the final velocity

u => is the initial velocity

t => is the time.

With the above formula, we can obtain the acceleration of the car as follow:

Initial velocity (u) = 25 m/s

Final velocity (v) = 0 m/s

Time (t) = 10 s

Acceleration (a) =?

a = (v – u) /t

a = (0 – 25) /10

a = –25 / 10

a = –2.5 m/s²

The acceleration of the car is –2.5 m/s². The negative sign indicate that the car is decelerating i.e coming to rest.

if the person is shown to have +90n, then ans is -10n.

if the person is shown to have -90n, then ans is +10n.