Suppose the matrix A is real but has complex eigenvalues. If the initial vector w in the power method is real, then all other quantities, including approximate eigenvalues, generated by the algorithm will be real. Hence if the eigenvalue of A of largest absolute value has nonzero imaginary part, then the power method will not converge to it. Can you explain this apparent paradox? (Hint: Can a real matrix have a complex eigenvalue li with nonzero imaginary part that satisfies [11] > [12] 2 ... 2 An]? Why or why not?)

x is the total time in minutes for the free response

you are given number of questions as 15 - m and time per item as 8 minutes

to find x multiply the two givens together:

x = 8 * (15-m) = 8(15-m)

answer: 40392

step-by-step explanation:

10098 x 4 = 40392

answer:

given the linear inequality :

add 2y to both sides we get;

simplify:

add 12 to both sides of an equation;

simplify:

divide both sides by 2 we get;

or

the related equation for the inequality equation [1] is;

y-intercepts defined as the graph crosses the y-axis.

substitute x =0 in [2] to solve for y;

y = 6

x-intercepts defined as the graph crosses the x-axis.

substitute value y = 0 to solve for x;

subtract 6 from both sides we get

multiply both sides by 2 we get;

or

x = -12

now, plot these point (0, 6) and (-12, 0) on graph as shown below and shade the graph below the solid line.

im super bad at school but u for some reason need to have points to ask questions and you get points by answering so thats all im doing sorry for t r o l l i n g  

∵⊃↔↓㏒㏒

: ⇔