Consider the equations of the circles given below. Rearrange the equations based on the ascending order of their radius. (x−20)2+(y−10)2=36\left(x-20\right) ^{2}+\left(y-10\right)^{2}=36(x−20)
2
+(y−10)
2
=36
x2+y2+22x−18y+186=0x^{2}+y^{2}+22x- 18y+186=0x
2
+y
2
+22x−18y+186=0
(x−5)2+(y+3)2=(7)2\left(x-5\right)^ {2}+\left(y+3\right)^{2}=\left(7\ri ght)^{2}(x−5)
2
+(y+3)
2
=(7)
2

x2+y2=25x^{2}+y^{2}=25x
2
+y
2
=25

correct answer is infinitely many solutions

step-by-step explanation:

2(2x + 3) = -4 + 2(2x + 5)

solving the above equation:

4x + 6 = -4 +4x +10

combining like terms

4x -4x = -4+10-6

0=0

since both sides are 0=0, we end up into true statement it means it has infinite many solutions.

so correct answer is infinitely many solutions

i would be 2,000 just get the square root of 50 which is 2500 and the divid 4/5 and last thing multiply the answer you get for that by the square root of 50

step-by-step explanation: