Problem PageQuestion Two cars leave towns 1000 kilometers apart at the same time and travel toward each other. One car's rate is 14 kilometers per hour less than the other's. If they meet in 5 hours, what is the rate of the slower car?

the rate of the slower car is 93 kilometers per hour.

Step-by-step explanation:

Two cars leave towns 1000 kilometers apart at the same time and travel toward each other. This means that by the time they meet, they would have travelled a total distance of 1000 kilometers.

Let x represent the rate of the slower car. One car's rate is 14 kilometers per hour less than the other's. This means that the rate of the faster car is (x + 14) km/h

Distance = speed × time

If they meet in 5 hours, then the distance covered by the slower car is 5x kilometers.

Also, after 5 hours, the distance covered by the faster car is 5(x + 14) kilometers.

Since the total distance covered is 1000 kilometers, then

5x + 5(x + 14) = 1000

5x + 5x + 70 = 1000

10x = 1000 - 70

10x = 930

x = 930/10

x = 93

i think this could be a possible answer (1 / 84) -1

good luck! : d