The fish population in a pond with carrying capacity 1200 is modeled by the following logistic equation where N(t) denotes the number of fish at time t in years. (dN)/(dt) = (0.4)/(1200)N(1200-N)
Starting at the time at which the number of fish reached 150, the owner of the pond removed (harvested) fish at a constant rate of 50 fish per year. We take t = 0 to be the time at which the owner started to harvest fish from the pond.

A) Modify the differential equation to model the population of fish from the time it reached 150.
dN/dt =

B) How far below the original carrying capacity will the number of fish be in the long run? (Give your answer correct to the nearest whole fish.)
Number of fish=