What is the equation of the line passing through the points (2, –1) and (5, –10) in slope-intercept form? a) y=3x-5 b) y=3x+5 c) y=3x-5 d) y=3+5

y = -3x+5  This has a negative slope

Step-by-step explanation:

The first step is to find the slope.  We can use the formula

slope = (y2-y1)/(x2-x1)

        = (-10--1)/(5-2)

       = (-10+1)/3

        = -9/3

       =-3

Next we will use the point slope form of the equation of a line

y-y1 = m(x-x1)

y--1 = -3(x-2)

y+1 = -3(x-2)

Distribute the -3

y+1 = -3x -3*(-2)

y+1 = -3x+6

Subtract 1 from each side

y+1-1 = -3x+6-1

y = -3x+5

This is in the slope intercept form of the equation.

My answer differs from the options because I have a negative slope

(f - g)(x) = 5x^3 - 3

step-by-step explanation:

rearrange these functions vertically, with like terms in separate columns:

f(x) = 5x^3 - 2

g(x) =         +1

now subtract, column by column:

(f - g)(x) = 5x^3 - 3

b). 4320 have a nice day