An electronics company can spend no more than $4,000 on raw materials for circuit boards. the raw materials cost $10 per ounce for copper and $20 per ounce for silver. to summarize the situation, a worker writes the inequality: 10c + 20s ≤ 4,000, where c is the number of ounces of copper material and s is the number of ounces of silver material. which graph's shaded region shows the possible combinations of raw materials the company can buy?

Option B (top of the 2nd column) is the correct answer.

Step-by-step explanation:

An electronics company can spend no more than $4,000 on raw materials for circuit boards.

The raw materials cost $10 per ounce for copper and $20 per ounce for silver.

Let us assume that,

c = the number of ounces of copper,

s = the number of ounces of silver.

The inequalities will be,

and

As the number of ounces used can not be in negative.

Plotting the graph and drawing the shaded region by origin test, we get the shaded region as attached below.

Therefore, option B (top of the 2nd column) is the correct answer.

i would have to say it is c.

answer: answer is c!

ok i got to organize the

3/15 and 12/55

3*

aha

3*4 equals 12 but not

a: no

b:

8/24 12/35

no

gautie

it's c

5/18 = 25/90

5*5=25

18*5 = 90

hope that you!

one more happy customer!

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step-by-step explanation: