Use the quadratic formula to find all degree solutions and θ if 0° ≤ θ < 360°. Use a calculator to approximate all answers to the nearest tenth of a degree. (Enter your answers as a comma-separated list. If there is no solution, enter NO SOLUTION.) cos2 θ + cos θ − 1 = 0 (a) all degree solutions (Let k be any integer.) θ = (b) 0° ≤ θ < 360° θ =

  or  

Step-by-step explanation:

  or  

The range of the cos θ function excludes θ = -1.61803, so we discard that solution.

  or  

c

step-by-step explanation:

it isn't d, because the interquartile range is from 27-57. and the interquartile range is basically half the data, it's pretty obvious.

it isn't b, because like i said earlier, the interquartile range is from 27-57. 57-27 is 30. the real range has to be longer

not a either. although it looks like it, 3/4 of the data is not greater than 27. but if c is wrong than this should be correct

the correct answer is c, because 13 is the point in which the plot starts

this shows a reflection over the x-axis and is translated one unit down and 6 units to the right (x + 6, y - 1)

hope this !

~just a girl in love with shawn mendes