The hypotenuse of a 45°-45°-90° triangle measures 18 cm. A right triangle is shown. The other 2 angle measures are 45 degrees. The length of the hypotenuse is 18 centimeters. What is the length of one leg of the triangle? 9 cm 9 StartRoot 2 EndRoot cm 18 cm

Step-by-step explanation:

Given

Hypotenus = 18cm

Required

Find the length of the other two sides

From the question, we understand that the other two sides are equal; let's represent them with x.

Pythagoras theorrem states that:

Substitute 18 for Hypotenuse

Divide both sides by 2

Take root of both sides

Split the above

Hence, the length of one leg is

m∠cdf = 43° , m∠gdf = 114°, m∠gde = 23°, m∠edh = 23° , m∠cdh = 157°

step-by-step explanation:

since, it is given that de bisects the angle gdh ⇒ de divides the angle gdh into two equal angles.

⇒ m∠gde = m∠edh

⇒ 8·x   - 1 = 6·x + 5

⇒ x = 3

so, m∠gde = 8·x - 1 = 23°

and m∠edh = 23°

now, it is given ∠cde is an straight angle so, m∠cde = 180°

⇒ m∠cdf + m∠fdg + m∠gde = 180°

⇒ 43° + m∠fdg + 23° = 180°

⇒ m∠fdg = 114°

again, m∠cde = m∠cdh + m∠edh = 180°

m∠cdh + 23° = 180°

⇒ m∠cdh = 157°

step-by-step explanation:

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