Solve the system by either the addition method or the substitution method.
x + 3y = 1
4x + 4y = -12

x = - 5

y = 2

Step-by-step explanation:

The given system of simultaneous equations is expressed as

x + 3y = 1 - - - - - - - - - - - - - -1

4x + 4y = -12 - - - - - - - - - - - 2

We want to eliminate x. Multiplying equation 1 by 4 and equation 2 by 1, it becomes

4x + 12y = 4

4x + 4y = - 12

Subtracting the second equation from the first equation, it becomes

8y = 16

y = 16/8 = 2

Substituting y = 2 into equation 1, it becomes

x + 3 × 2 = 1

x + 6 = 1

x = 1 - 6 = - 5

8(-10x+3.5y-7)

8×-10x + 8×3.5y + 8×-7

-80x + 28y - 56

therefore

-80x+28y-56 is the correct answer

i do not know the answer

step-by-step explanation: