How many moles of molecules are in 10 g of aspartame?

The moles of molecules are in 10 g of aspartame - 0.034 × 10¹⁹

The number of molecules of a given mass of a substance using the molar mass of the substance and Avogadro's constant, 6.022 × 10²³

The number of moles =

=

= 0.034 × 10 ⁻⁵ mole

Using Avogadro's constant, we can convert this value to molecules as so:

= 0.034 × 10 ⁻⁵ (6.022 × 10²³)

= 0.034 × 10¹⁹

Thus, the moles of molecules are in 10 g of aspartame - 0.034 × 10¹⁹

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Explanation:

Data Given:

mass of aspartame = 10 g

molecules of aspartame = ?

Solution

First we calculate no. of moles of 10 g aspartame

For which mole formula will be used

               no. of moles = mass in grams / molar mass . . . . . . .(1)

Formula of aspartame:

C₁₄H₁₈N₂O₅

So,

The molar mass of aspartame (C₁₄H₁₈N₂O₅) will be

molar mass of C₁₄H₁₈N₂O₅ = 14(12) + 18(1) + 2(14) +5(16)

molar mass of C₁₄H₁₈N₂O₅ = 168 + 18+ 28 + 80

molar mass of C₁₄H₁₈N₂O₅ = 294 g/mol

put values in equation 1

          no. of moles = 10 g / 294 g/mol

          no. of moles = 0.034 mol

now we will calculate no. of molecules

Formula will be used

           no. of moles = no. of molecules / Avogadro's number

Rearrange the above equation:

no. of molecules = no. of moles x Avogadro's number . . . . . (2)

Where

Avogadro's number = 6.022 x 10²³

Put values in equation 2

           no. of molecules =0.034 mol x 6.022 x 10²³ (molecules/mol)

           no. of molecules = 2.0475 x 10²²

So,

There are 2.0475 x 10²² molecules are in 10 grams of aspartame that is 0.034 moles of aspartame.

So,  in turn its 0.034 moles of molecules are in 10 g of aspartame.

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the dissolution of polymer can be thermodynamically described in 2 steps.