Write the point from of the equation for a line that passes through (6,—1) with a slope of 2

y = 2x-13

Step-by-step explanation:

The equation for a line is

y = mx+b where m is the slope and b is the y intercept

y = 2x+b

We know a point so we have a y and an x, so we can solve for b

-1 = 2(6) +b

-1 =12+b

Subtract 12 from each side

-1-12 = 12-12+b

-13 =b

Substitute this into y = 2x+b

y = 2x-13

The equation for point-slope form is: y - y1 = m( x - x1)

We already know from what is given in the question that:

The value of x1 is: 6

And the value of y1 is: 1

Now all you have to do is plug it in:

y - (-1) = 2[x – (6)]

And then simplify:

y + 1 = 2( x - 6)

I hope this helps! :)

i not know

step-by-step explanation: