In a different plan for area codes, the first digit could be any number from 0 through 6, the second digit was either 0,1, or 2,and the third digit could be any number except 6. With this plan how many different area codes are possible?

let's solve your equation step-by-step.

4x+2=2x+12

step 1: subtract 2x from both sides.

4x+2−2x=2x+12−2x

2x+2=12

step 2: subtract 2 from both sides.

2x+2−2=12−2

2x=10

step 3: divide both sides by 2.

2x

2

=

10

2

x=5

step-by-step explanation:

nothjing

step-by-step explanation:

x> 6

step-by-step explanation:

8x+8> 7x+14

8x-7x> 14-8

x> 6