The noise from a power mower was measured at 106 db. the noise level at a rock concert was measured at 115 db. find the ratio of the intensity of the rock music to that of the power mower. (round your answer to the nearest whole number.)

= 8

Explanation:

noise from power mower = 106 dB

noise from rock concert = 115 dB

we would be applying the formula for the decibel level of sound to get the intensities.

(B) = 10 log \frac{I}{I₀}

I = intensity of sound

I₀= reference intensity = 10^{-12} W/m^{2}

106 = 10 log \frac{I}{10^{-12}}

10.6 =  log \frac{I}{10^{-12}}

10^{10.6} = \frac{I}{10^{-12}}

I = 10^{10.6} x 10^{-12}

I of power mower = 0.0398 W/m^{2}

115 = 10 log \frac{I}{10^{-12}}

11.5 =  log \frac{I}{10^{-12}}

10^{11.5} = \frac{I}{10^{-12}}

I = 10^{11.5}  x 10^{-12}

I of rock music = 0.316 W/m^{2}

now the ratio of the intensity of the rock music to the power mower

= \frac{0.316}{0.0398}

= 8

there are no correct statementd on the list of choices you provided.

  the unit of the measure =

explanation:

  the property that is quantified by the energy needed per of material to raise the temperature by one.

  si unit of energy = joule (j)

  si unit of temperature = kelvin (k)

  si unit of mass of material = kilogram (kg)

the property that is quantified by the energy needed per of material to raise the temperature by one is called specific heat.

the unit of specific heat is