−3(a–b) < 0, which is the greater: a or b? Give numerical examples.

a>b

Step-by-step explanation:

−3(a–b) < 0

Divide each side by -3, remembering to flip the inequality since we are dividing by a negative

−3(a–b)/-3 > 0/-3

a-b > 0

Add b to each side

a-b+b > 0+b

a >b

a is greater than b

Let a = 5 and b = 4

−3(5–4) < 0

-3 (1) < 0

-3 <0  True

If a <b  Then it would be false

Let a = 5 and b =7

−3(5–7) < 0

-3 (-2)<0

6< 0  this is false

answer: x

step-by-step explanation:

answer:   the paragraph proof is mentioned below.

step-by-step explanation:

given: in a δxwy where

such that, ∠wzx ≅ ∠yzx and zw≅zy

we have to prove that: segment zx is a perpendicular bisector of segment wy.

prove: since, zw≅zy ⇒ ∠wzy is a supplementary angle.

then, ∠wzy= 180°

⇒∠wzx + ∠yzx = 180° ( because xz divides ∠wzy into two parts)

but, ∠wzx ≅ ∠yzx ( given)

⇒∠wzy+∠wzy=180° ( by substitution)

⇒2∠wzy=180°

⇒∠wzy=90°

⇒∠wzy=∠yzx =90°

therefore, xz⊥wy where wz=zy

⇒zx is a perpendicular bisector of wy.