A catapult is designed to launch circus performers from a raised platform. After launch, the height of the performer in feet is given by h left parenthesis t right parenthesis equals minus 16 t squared plus 80 t plus 32 where t is seconds after launch. After how many seconds is the performer exactly 100 feet above the ground? Round to the nearest tenth of a second.

t = 1.1 sec for first time and then in

t = 3.9 sec

Step-by-step explanation:

The function for the height of the circus performers is:

                             where t is seconds after launch

                                        h is height in feet

For calculating after how many seconds is the performer at 100 feet above the ground, we must equal the equation to 100 and to find t:

Then,

t = 3.9 sec

t = 1.1 sec

i can't solve unless i know what the line is

step-by-step explanation:

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