Let f(x)=x+a/x+b such that f(f(1)=0 & f(2)=-3 then a& b resctivily are.

a, 1,-5/3 b, -5/3,3 c, 1,-3 d, none of the above

The value of a = - 1  ,   And b =    

Step-by-step explanation:

Given as :

Function f(x) =

And f(f(1)) = 0     And f(2) = - 3

Now For , x = 2 , y = - 3

I.e  f(2) =

or,  - 3 =

I.e 2 + a = - 6 - 3b

Or, a + 3b = - 8               ....... 1

Again  f(f(1)) = 0

So,   = 0

Or,  1 + a = 0

∴    a = - 1

So , put htis value of a i n eq 1 , we get value of  b

So , - 1 + 3b = - 8

Or,   3b = - 7

∴       b =

Hence The value of a = - 1  ,   And b =    Answer

the answer is b.

step-by-step explanation:

identity property is where 0+whatever number=whatever number. basically 0+ a number.

let's solve your equation step-by-step.

4x+2=2x+12

step 1: subtract 2x from both sides.

4x+2−2x=2x+12−2x

2x+2=12

step 2: subtract 2 from both sides.

2x+2−2=12−2

2x=10

step 3: divide both sides by 2.

2x

2

=

10

2

x=5

step-by-step explanation: