aqueous potassium iodate (kio3) and potassium iodide (ki) react in the presence of dilute hydrochloric acid (hcl), as shown below. kio3(aq) + 5ki(aq) + 6hcl(aq)  3i2(aq) + 6kcl(aq) + 3h2o(l) what mass of iodine (i2) is formed when 15.0 ml of 0.0050 m kio3 solution reacts with 30.0 ml of 0.010 m ki solution in the presence of excess hcl?

the answer would be c

the answer is:

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