10+(5v-7)=5v-3
answer this linear equation

10+(5v-7)=5v-3

pretend that there is a 1 in front of the bracket

10+1(5v-7)=5v-3

mutiply the bracket by 1

(1)(5v)= 5v

(1)(-7)= -7

10+5v-7= 5v-3

10-7+5v= 5v-3

3+5v=5v-3

move 5v to the left side

sign changes from +5v to -5v

3+5v-5v= 5v-5v-3

3+0= 0-3

3=-3

no solution

answer: 370

step-by-step explanation:

remember use pemdas! there are no parentheses or exponents so lets move onto the first part of the equation: multiplication and division. first, lets break the first part of the equation up into something easier using the distributive property. 28 * 12= (20 *12) + (8*12) you know that 20*12 is 240 and 8*12 is 96. add them and you get 336. then, lets solve the last part of the equation (the last part of pemdas is addition and subtraction). 336 plus 34 is 370. hope this !

step-by-step explanation:

just plug in each number for x and see which ones work and don't