Suppose you have already been waiting for one hour for a taxi. what is the probability that one arrives within the next 10 minutes?

The probability of one arrives within the next 10 minutes when he already been waiting for one jour for a taxi is,

P (X > 70 | X > 60) = P (X > 10) = 1 – P (X ≤ 10) = 1 – {1 – e ^ -((1 / 10) 10)} = e ^ -1

= 0.3679

The probability of one arrives within the next 10 minutes when he already been waiting for one hour for a taxi is 0.3679

-7/8

step-by-step explanation:

instead of subtracting you add the -6/8 and -1/8

answer: (c) m∠qpo + (2x + 16)° = 180°

step-by-step explanation:

the opposite angles of a quadrilateral are supplementary.

so, ∠o + ∠q = 180°   and   ∠p + ∠r = 180°

since ∠r = 2x + 16°, we can use substitution as follows:

∠p + ∠r = 180°

∠p + (2x + 16)° = 180°