Walt and amy each have the same number of pennies. walt made equal stacks of 10 pennies with none left over. amy made equal stacks of 8 pennies with none left over. what is the least number of pennies that each person could have? explain how you found your answer.

40 coins

Step-by-step explanation:

Note that

To find the least common multiple you have to multiply all common multiplies and then multiply them by all factors that left. Thus,

This means that if Walt and Amy each have 40 coins, then Walt can make 4 stacks with 10 coins in each and Amy can make 5 stacks with 8 coins in each.

d, x=8

step-by-step explanation:

simplifying

4x + -5 = 2x + 11

reorder the terms:

-5 + 4x = 2x + 11

reorder the terms:

-5 + 4x = 11 + 2x

solving

-5 + 4x = 11 + 2x

solving for variable 'x'.

move all terms containing x to the left, all other terms to the right.

add '-2x' to each side of the equation.

-5 + 4x + -2x = 11 + 2x + -2x

combine like terms: 4x + -2x = 2x

-5 + 2x = 11 + 2x + -2x

combine like terms: 2x + -2x = 0

-5 + 2x = 11 + 0

-5 + 2x = 11

add '5' to each side of the equation.

-5 + 5 + 2x = 11 + 5

combine like terms: -5 + 5 = 0

0 + 2x = 11 + 5

2x = 11 + 5

combine like terms: 11 + 5 = 16

2x = 16

divide each side by '2'.

i belive those are the ones that are under 90 degreese.