An urn contains balls numbered 1 to 15 a ball is chosen returned to the urn and the second ball is chosen what is the probability that the first and the second of all will be a six

Step-by-step explanation:

An urn contains balls numbered from 1 to 15

Total number of outcomes= 15

Let E1 be event of getting a ball numbered 6

Favorable case to E1= 1

Probability=

P(E1)=

A ball is chosen and returned to urn

Again, total number of outcomes=15

Let E2 be event of getting a ball numbered 6

Favorable case to E2= 1

P(E2)=

The Probability that the first and second ball is 6=P(E1)+P(E2)

=+

=

Hence, the correct answer is

step-by-step explanation:

graph using a few selected

x         y

-1       15

0         6

1         2.4

2       0.96

(5x-1)^2= (5x)^2-2(5x)×1+(1)^2=25x^2-10x+1