If 5.17 g of an unknown substance X, which is a nonelectrolyte, lowers the freezing point of 200g of benzene ( k = 4.9 C-/m) by 0.84 C what is the molecular weight of X?

Explanation:

Hello there!

In this case, according to the given information, it turns out firstly possible for us to set up the equation for the freezing point depression as shown below:

Thus, given Kf, i (equal to 1 because it is nonelectrolyte) and the freezing point depression, we can now calculate the molality of the solution:

Next, we calculate the kilograms of solvent by dividing the 200 g by 1000 to get 0.200 kg and thus calculate the moles of the solute X:

Finally, the molar mass by dividing the grams by moles:

Regards!

c most likely

hop this let me know if it is wrong

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