In the following balanced reaction, what volume of a 3.0 m h2so4 is required to completely neutralize 200.0 ml of a 2.5 m naoh? h2so4 + 2naoh → na2so4 + 2h2o a. 200 ml b. 83 ml c. 50 ml d. 170 ml

B) 83 mL

Find the moles of NaOH by using Molarity=moles/volume(L) so Moles = molarity x volume.

Then use the mol ratio to go from moles of NaOH to moles of H2SO4 by dividing the moles of NaOH by 2. Now you're in moles of H2SO4 so again use M = moles/Volume to find the volume. Volume = moles/M.

(The volume is in Liters in the equation but you can use the mL on this problem because your conversions cancel each other out.)

B Plato

Explanation:

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