Im not sure how to figure this circuit out

Yes, this is certainly ugly and scary.
Here's how to go about it:

-- Take the two resistors in the middle ... the  9  and the  8 .
   They're in parallel.
   Their equivalent resistance is something like 4.24 ohms.  Whatever.

-- Take the two resistors around the outside on the right ... the 4 and the 6 .
    Together, in series, they're equivalent to  10 ohms.

-- That 10 ohms is in parallel with the ~4.24 ohms in the box.
    Now you have something like  2.98 ohms, all to the right of the 3 on top.

--  That 2.98 is in series with the 3.0 on top.
     So there's  5.98 ohms.

-- The 20.0 is in parallel with the  5.98 ohms.
    So that's about 4.6 ohms equivalent between 'A' and 'B'.

That's just off the top of my head.  I won't sharpen it down
any further than that, because it's only 5 points, and you
should be able to do it now, using this approach.

Ithink your answer is d