Where is the center of gravity if the 9.00 kg mass of the barbell itself is taken into account?

The problem is missing some parts but nevertheless here is the

Given:

1.7 m long barbell with 23 kg weight on the left and 34 in the right end.

Solution:

 Calculating from the left side:

Center of gravity = ΣM/ΣW = [23*0 + 9*(1.7/2) + 34*1.7]/[23+9+34] 

Center of gravity = .992 m from the left end

beta is electron from nucleus

something from nucleus has changed, but charge must be same for cons of charge

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