If a glass is knocked off of a table that is 1.4 m tall, how long does it take for the glass to hit the ground? sorry im having so much trouble can anyone explain what to do

The formula we can use in this case would be:

h = vi t + 0.5 g t^2

where h is height, vi is initial velocity = 0 since started from rest, g is gravity

Therefore calculating for t:

1.4 m = 0.5 * 9.8 m/s^2 * t^2

t^2 = 0.2857 s^2

t = 0.53 seconds

d. learned preferences i believe is your answer

f=ma a/f/m a= 480/60 a = 8m/s/s that is quick wow