Particles q1, 92, and q3 are in a straight line. Particles q1 = -5.00 x 10-6 C. q2 = +2.50 x 10-6 C,
and q3 = -2.50 x 10-6 C. Particles q1 and q2 are
separated by 0.500 m. Particles q2 and q3 are
separated by 0.250 m. What is the net force on q2?
Remember: Negative forces (-F) will point Left
Positive forces (+F) will point Right
-5.00 x 10-6 C
+2.50 x 10 6
-2.50 x 10-6 C
91
92
93
0.500 m
0.250 m

their crystal patterns have been disrupted by stress

mass and volume are the answers you are looking for

weight of the box is given as

here this is placed on the inclined of angle 42 degree

now this weight will have two components one is along the incline other is perpendicular to it

so here we need to apply a force parallel to incline opposite to its component of weight

so here the component of weight is given as

here we have

so it requires 75 n force to move it upwards