11. A .223 rifle bullet, traveling at 370.m/s, hits a block of pine wood, and goes in, to a depth of 0.130m. The mass of the bullet is 1.75g (mass = 0.00175kg). Assume a constant slowing force. (a) What is the acceleration that the bullet experiences as it comes to a stop? (b) How much
time is required for the bullet to stop? (c) What force, in Newtons, does the wood exert on the
bullet?

0.55x745.7j and a calculator

i don't know that i agree with that but what's the question ?

3.2x10^7

initial speed when it is dropped is 150 ft/s

now at the same moment the acceleration due to gravity is perpendicular to its velocity

so as we know that

now we have centripetal acceleration a = 32 ft/s^2 as its perpendicular to velocity

while tangential acceleration at the same moment will be zero

so

now radius of curvature is given as

so the radius of curvature just after it is dropped is 703.125 ft