The concentrations of reactants and products for a chemical reaction can be calculated if the equilibrium constant for the reaction and the starting concentrations of reactants and/or products are known. part a carbonyl fluoride, cof2, is an important intermediate used in the production of fluorine-containing compounds. for instance, it is used to make the refrigerant carbon tetrafluoride, cf4 via the reaction 2cof2(g)⇌co2(g)+cf4(g), kc=8.80 if only cof2 is present initially at a concentration of 2.00 m, what concentration of cof2 remains at equilibrium? express your answer with the appropriate units.

0.28 M

Explanation:

Concentration of [COF₂] = 2.00 M

Considering the ICE table for the equilibrium as:

                     2COF₂ (g)      ⇔          CO₂ (g) +       CF₄ (g)

t = o                2.00

t = eq                -2x                             x                      x

--------------------------------------------- --------------------------

Moles at eq:    2.00-2x                        x                      x

The expression for the equilibrium constant is:

So,

Solving for x, we get that

x = 0.86 M

Equilibrium concentrations :

[CO₂] = [CF₄] = 0.86 M

[COF₂] = 2.00 - 2*0.86 = 0.28 M

look at the !

pleaze mark brainliest!

the enthalpy of formation of water is given as -285.8kj/mol, which states that the enthalpy of formation is negative.

negative enthalpy of formation indicates that the heat is released during the reaction process. the heat is released from reaction to the surroundings the enthalpy is expressed with a negative sign with the energy given out in the reaction process.

the formation of water takes place by giving out heat which is -285.8 kj/mol.