given an oil droplet of mass 0.9mg and density 918kg/m^3 that spreads out into a circle of a radius 41.8cm on the water surface what is the diameter of the oil molecule​

The diameter of the oil molecule is  .

Explanation:

Mass of the oil drop =

Density of the oil drop =

Volume of the oil drop: v

Thickness of the oil drop is 1 molecule thick.So, let the thickness of the drop or diameter of the molecule be x.

Radius of the oil drop on the water surface,r = 41.8 cm = 0.418 m

1 cm = 0.01 m

Surface of the sphere is given as: a =

Volume of the oil drop = v = Area × thickness

The thickness of the oil drop is  and so is the diameter of the molecule.

what are the statements? x

when two balls of the different masses are dropped from equal height, they reach the ground at the same time .this is because they experience the same acceleration.

the acceleration is independent of mass.

thus when they are dropped they will always maintain the same velocity and travel the same distance (neglect air resistance of course) at the same time.