A drag racer starts from rest and accelerates at 43 m/s2. After 2.9 seconds of this constant acceleration, how far down the track is the dragster? (Answer in meters)

180 meters

Explanation:

We know initial position and velocity of the dragster are both zero. We only know acceleration (43 m/s^2) and need to find out how far the dragster moves after 2.9 seconds.

x initial = 0

velocity initial = 0

t=2.9s

a= 43m/s^2

Plug into

180 meters or 1.8 x 10^2 meters is the answer accounting for 2 sig figs.

energy stored in the capacitor= 9.72 x 10⁻⁴ j

explanation:

the energy stored in the capacitor is given by

e= 1/2 c v²

e= energy stored

c= capacitance= 1.5 µc= 1.5 x 10⁻⁶f

v= potential difference=36 v

so energy stored= e= 1/2 (1.5 x 10⁻⁶) (36)²

energy stored= 9.72 x 10⁻⁴j