Consider a sequence whose five terms are: 3, 9, 27, 81, 243 Which function ( with domain all integers could used to define and continue this sequence

a(n)=3^n as an infinite sequence

I do not know whether you've been introduced to series notation yet, though if you haven't, a(n)=3^n pertains to sequences specifically.

a(n) = 3^n = {3^1, 3^2, 3^3, 3^4, 3^5...}

Which equals 3^n = {3, 9, 27, 81, 243...}

5x+2x=49

7x=49

x=7. 35 apples

$9.89

step-by-step explanation:

9.90 = p x .06 x .25 (3/12 changed to a decimal)

9.90 = p x 0.015

9.90 - 0.015 = p

9.89 = p