13 The pressure of the atmosphere is 100 000 Pa a Calculate the force with which the atmosphere presses on the outside of a large window 2.0m
high and 1.25m wide.
bExplain why this force does not break the window.

Question:-

(A) The pressure of the atmosphere is 100000 Pa Calculate the force with which the atmosphere presses on the outside of a large window 2.0m high and 1.25m wide.

(B) Explain why this force does not break the window.

-

(A)

As we know

Given->

Pressure-> 1atm

height-> 2 m

wide -> 1.25 m

Putting value in formula ->

(B) Because atmosphere is present on both sides of the window pane so same force is applied from both sides of the window and as we know force is a vector quantity so according to the vector sum the force got cancelled out and net force becomes zero .

That's why even in presence of this amount of force window glass donot break

    m₁v₁ + m₂v₂ = (m₁ + m₂)vmomentum is conserved.the left-hand side of the equation represents the momentum in the system before the collision.the right-hand side represents the momentum in the system after the collisionm₁ and v₁ represents the mass and the velocity of the physics blockm₂ and v₂ represents the mass and velocity of the ball of puttyv represents the final velocity of the combined mass.the question states the two masses stick together. they combined mass has its own velocity with the body mass the sum of the two objects' massestheir combined momentum is (m₁ + m₂)vto find the magitude of (m₁ + m₂)v, we need to add the vectors on the left-hand side of the equation: m₁v₁ + m₂v₂.note the diagram. i have positioned the vectors in accordance with their directions.the magnitude of the resultant can be calculated using the pythagorean theorem since this is a right triangle situation (north and west are perpendicular)|(m₁ + m₂)v| =  √[ (m₁v₁)² + (m₂v₂)² ]|(m₁ + m₂)v| =  √[ (1.5kg·8.0m/s)² + (0.40kg·20m/s)² ]|(m₁ + m₂)v| =  14.4 kg m/sfor two significant figures (assuming that 20m/s is two), this rounds to 14 kg m/s

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