Physics, 07.06.2021 01:00 BaileyElizabethRay

50N force accelerated a body at a rateof 8 metres per second square. Calculate the mass of the body

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Answer from: Buddy01

$\boxed {\boxed {\sf 6.25 \ kilograms}}$

Explanation:

According to Newton's Second Law of Motion, force is the product of mass and acceleration.

$F= m \times a$

We know the force is 50 Newtons and the acceleration is 8 meters per second squared. Let's convert the units to make the problem and unit cancellation easier.

1 Newton is equal to 1 kilogram meter per square second (1 kg*m/s²), so the force of 50 N is equal to 50 kg*m/s².

Now we know 2 values:

F= 50 kg*m/s²a= 8 m/s²

Substitute the values into the formula.

$50 \ kg *m/s^2= m \times 8 \ m/s^2$

Since we are solving for the mass, we must isolate the variable, m. It is being multiplied by 8 meters per square second and the inverse of multiplication is division. Divide both sides by 8 m/s².

$\frac {50 \ kg *m/s^2}{8 \ m/s^2}= \frac{m \times 8 \ m/s^2}{8 \ m/s^2}$

$\frac {50 \ kg *m/s^2}{8 \ m/s^2}= m$

The units of meters per square second (m/s²) cancel.

$\frac {50 \ kg }{8 }=m$

$6.25 \ kg =m$

The mass is 6.25 kilograms.

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the electric field is a “force field” around a charged object that illustrates the direction the electric force would push an imaginary

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scattering of light by tiny particles in air to produce the colors we see on sky, is dependent on the following factors:

(i) wavelength of light

(ii) size of the scattering particle

(iii) distance traveled by light through the atmosphere.

according to rayleigh's law of scattering, the amount of scattering is inversely proportional to the fourth power of its wavelength. shorter the wavelength, greater is its scattering. hence violet/blue light is scattered more than red.

sun's light is a composite light ( visible light) with wavelengths in the range 400 nm (violet) to 700 nm (red). as sunlight passes through our atmosphere, the molecules of air scatter light according to their wavelengths. during sunrise and sunset, the sun's position is below the horizon. hence light from the sun travels a greater distance in the atmosphere when compared to its position a noon.

as sunlight enters the earth's atmosphere, blue light is scattered away and at the end of its journey in the sky, only red and orange wavelengths remain in the beam.

hence at sunrise and sunset, the sky appears reddish orange.

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