Silver chloride, agcl (ksp = 1.8 x 10‒10), can be dissolved in solutions containing ammonia due to the formation of the soluble complex ion ag(nh3)2 + (kf = 1.0 x 108 ). what is the minimum amount of nh3 that would need to be added to dissolve 0.010 mol agcl in 1.00 l of solution?

Explanation:

The given reaction will be as follows.

            ............. (1)

      =

Reaction for the complex formation is as follows.

          ........... (2)

          =

When we add both equations (1) and (2) then the resultant equation is as follows.

              ............. (3)

Therefore, equilibrium constant will be as follows.

                       K =

                          =

                          =

Since, we need 0.010 mol of AgCl to be soluble in 1 liter of solution after after addition of for complexation. This means we have to set

                =

                          =

                          = 0.010 M

For the net reaction,

Initial :                             0.010         x                     0                           0

Change :                    -0.010         -0.020             +0.010                +0.010

Equilibrium :                   0            x - 0.020           0.010                 0.010

Hence, the equilibrium constant expression for this is as follows.

              K =

      =

             x = 0.0945 mol      

or,          x = 0.095 mol (approx)

Thus, we can conclude that the number of moles of needed to be added is 0.095 mol.

2b2t

explanation:

2b2t

1.43 x 10^-11 j the guy commented the awnser just making sure u see it .