Asand core used to form the internal surfaces of a steel casting experiences a buoyancy force of 225 n. the volume of the mold cavity forming the outside surfaces of the casting = 4840 cm3. what is the weight (in kg) of the final casting? ignore considerations of shrinkage

Newton’s second law gives us the relationship of force F, mass m and acceleration a. The formula is given as:

F = m a                  --> 1

However we also know that the relationship of mass m, density ρ, and volume V is:

m = V ρ                 --> 2

Therefore substituting equation 2 to equation 1:

F = ρ V a = ρ V g

where a is acceleration due to gravity, ρ is density of water and V is the volume of the casting, therefore:

F = (1x10^-3 kg/cm^3) (4840 cm^3) (9.8 m/s^2)

F = 47.432 kg m/s^2

F = 47.432 N

Going back to equation 1:

47.432 N = m (9.8 m/s^2)

m = 4.84 kg

Hence the weight of the final casting is 4.84 kg

the displacement produced by the body.  

the amount of force subjected to the body.  

the angle between the direction of force and displacement