Apoint charge of 6.8 c moves at 6.5 × 104 m/s at an angle of 15° to a magnetic field that has a field strength of 1.4 t.
what is the magnitude of the magnetic force acting on the charge?

a. 1.6 × 10^–1 n
b. 6.0 × 10^–1 n
c. 1.6 × 10^5 n
d. 6.0 × 10^5 n

Force exerted on a movimg charge in a magnetic field, only considers velocity perpendicular to the field; in this case, the charge is moving at an angle 15°, the perpendicular velocity is: Speed * SIN °15

FORCE = CHARGE * SPEED * MAGNETIC STRENGTH

= 6.8 * (6.5x10^4xSIN15°) * 1.4 = 1.6 x 10^5

Answer C.