The distance between the two nearest points on a wave where the particles are in phase is 2 m. What is the wavelength of the wave? A. 1/2 m

B. 1 m

C. 2 m

D. 2 seconds

E. none of these

Suppose that the wave equation is:

f(x) = A*cos(k*x)

The wave is in phase for two points x₁ and x₂ if:

f(x₁) = f(x₂)

And if these points are consecutive (for example, two consecutive peaks) then the wavelength of the wave is:

wavelength = x₂ - x₁

In this case, we know that the wave is in phase for two points that are 2 m apart.

Then we can use the points:

x₁ and x₂ such that:

x₂ = x₁ + 2m

We also know that these are the nearest points such that this happens, then we can assume that the points are consecutive.

Then the wavelength will be:

wavelength = x₂ - x₁ = (x₁ + 2m) - (x₁) = 2m

Then the wavelength is 2m.

The correct option is C.

jupiter is the largest planet in our solar system, having a mass and radius that are respectively, 318 and 11.2 times that of earth. suppose that an object falls from rest near the surface of each planet and that the acceleration due to gravity remains constant during the fall. each object falls the same distance before striking the ground. determine the ratio of the time of fall on jupiter to that on earth.

we're given that v₀ = 0 and a = 5.4 m/s². therefore, since v = at + v₀ for constant acceleration the equation for velocity is

after 28s,

m/s

which i would round to 150 m/s as my final answer