a force 4000 n accelerates a car of mass 800 kg from rest to 20 ms how far does the car travel while the force is acting?​

d = 40 m

Explanation:

Given that,

Force, F = 4000 N

Mass of a car, m = 800 kg

Initial velocity, u = 0 (at rest)

Final velocity, v = 20 m/s

We need to find the distance traveled. Force acting on a car is given by :

F = ma

Where

a is the acceleration of the car.

Let it has traveled d distance. Using third equation of motion.

So, the required distance is equal to 40 m.

the working equation for the angular size is the product of the physical size and 360 degrees divided by the product of two pi and distance from earth. the minimum size would be 0.559 degrees while the maximum size would be 0.49 degrees. 

beta is electron from nucleus

something from nucleus has changed, but charge must be same for cons of charge