How far must a spring with a spring constant of 64N/m be stretched to store 0.32J of potential energy?

0.1m

Explanation:

k = 64N/m

Ep = 0.32J

x = ?

Ep = 1/2 * kx²

make x the subject of the formula

x² = 2Ep/k

x = √(2Ep/k)

x = √(0.64/64)

x = √0.01

x = 0.1m

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305.7

explanation:

density =m/v

density =917/3.00

density = 305.

approximately = 305.7

in four significant figures