Two carts of masses of 5.0 kilograms and 1.0 kilogram are pushed apart by a compressed spring. If the 5.0-kilogram cart moves westward at 2.0 meters per second, the magnitude of the velocity of the 1.0-kilogram cart will be

The magnitude of the velocity of the 1.0-kilogram cart will be 10 m/s Eastward direction.

Explanation:

Given;

mass of the first cart, m₁ = 5.0 kg

mass of the second cart, m₂ = 1.0 kg

velocity of the first cart, v₁ = 2 m/s

velocity of second cart, v₂ = ?

Apply the principle of conservation of linear momentum;

m₁v₁ + m₂v₂ = 0

m₁v₁ = -m₂v₂

(5 x 2) = -(1 x v₂)

10 = -v₂

v₂ = - 10 m/s (the negative sign indicates Eastward direction)

Therefore, the magnitude of the velocity of the 1.0-kilogram cart will be 10 m/s Eastward direction.  

the ima (higher than 1m) will be greater than the ima with the height of 1m.