A sled weighs 10.0 kg. It is held in place on a frictionless 20.0-degree slope by a rope attached to a stake at the top of the slope. Find the tension in the rope if it is parallel to the slope. 47.9 N 37.4 N

33.5 N

Explanation:

Given that

Mass of the sled is, m = 10 kg

Angle of slope, θ = 20°

The tension in the rope of its parallel to the slope is often given as

W * sinθ, where

W = Force on the rope and

θ = angle of the slope

Now, remember that

w = mg, where g = acceleration due to gravity, so

W = 10 kg * 9.81 m/s²

W = 98.1 N,

Going ahead to solve for tension in the slope, we have

T = W * sinθ

T = 98.1 * sin20

T = 98.1 * 0.342

T = 33.5 N

Tension in the slope is 33.5 N

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