A ball is thrown with a speed of 100 ft/s in a direction of 30 degrees above the horizontal. determine the horizontal distance in m, the time of flight, and the height to which it rises..Note: you have to label your answer and final answer must be two decimal place

Horizontal distance covered is  270.63ft

Time of flight is 3.125secs

Height to which it rises is 39.06feet

Explanation:

The horizontal distance covered is the range;

Range = U²sin2theta/g

Range = 100²sin2(30)/32

Range = 10000sin60/32

Range = 10000(0.8660)/32

Range = 8660/32

Range = 270.625ft

Hence the  horizontal distance covered is  270.63ft

The time of flight is expressed using the formula;

T = 2Usin theta/g

g is the acceleration due to gravity

T = 2(100)sin30/32

T = 200(0.5)/32

T = 100/32

T = 3.125secs

Hence the time of flight is 3.125secs

Maximum height H = u²sin²theta/2g

H = 100²(sin30)²/2(32)

H = 10000(0.5²)/64

H = 10000(0.25)/64

H = 2500/64

H = 39.0625

Hence the height to which it rises is 39.06feet

grav potential energy