An airplane travels at 500.0 km/hr W. It encountered a south bound cross-wind and ends up with a velocity of 625 km/hr SW. What was the velocity of the cross-wind? Be sure to record your answer to the correct precision!

The velocity of the cross-wind was 375 km/hr South

Explanation:

The given speed of the airplane, v₀ = 500.0 km/hr W

The direction the airplane is headed = West

The direction of the wind encountered = Southbound wind

The final velocity of the airplane, R = 625 km/hr

The final direction of the airplane = South West SW

Let vₐ represent the velocity of the cross-wind

Therefore, we have the given velocities in vector form as follows;

R = -500.0·i - vₐ·j

Also, we have;

625² = (-500)² + (-vₐ)²

(-vₐ)² = 625² - (-500)² = 140625

-vₐ = 375

vₐ = -375 km/hr North = 375 km/hr South

The velocity of the cross-wind = vₐ = 375 km/hr South

it about 600 mph from what i calculated

answer: the direction of the wind is expressed as the direction from which the wind is blowing. for example, easterly winds blow from east to west, while westerly winds blow from west to east.

explanation: