A light spring obeys Hooke's law. The spring's unstretched length is 33.5 cm. One end of the spring is attached to the top of a doorframe and a weight with mass 7.00 kg is hung from the other end. The final length of the spring is 42.0 cm. What if

807.88N/m

Explanation:

The  question has some missing details in it, nevertheless, based on the given data we want to find the spring constant K

Step one

given data

Unstretched length = 33.5 cm

Final length of the spring = 42.0 cm

Δx= 42-33.5

Δx=8.5cm to m= 0.085m

mass m= 7kg

The force on the spring

F=mg

F= 7*9.81

F=68.67N

Step two:

From Hooke's law, we can make k subject of formula and find the spring constant k, we have

F=kΔx1

make k subject of the formula

k=F/Δx

k= 68.67/ 0.085

k=807.88N/m

i think it’s a. this is because if they measured the mass of something with a mass of 150g, then their final answer would have to be approximately 150g. though all of their answers are almost 150, rosa and tran have the closest answers (or the exact answer) to the accurate one.