Sully is riding a snowmobile on a flat, snow-covered surface with a constant velocity of 10 meters/second. The total mass of the snowmobile, including Sully, is 280 kilograms. If Sully accelerates to a velocity of 16 meters/second over 10 seconds, what’s the force exerted by the snowmobile to accelerate? Use F = ma, where . A. 160 N B. 168 N C. 248 N D. 280 N E. 324 N

280.6N

Explanation:

According to Newton's second law;

Force = mass * acceleration

Given

Mass = 280kg

velocity = 10m/s

Time = 10 secs

Acceleration = velocity?/Time

Force = mass * velocity/time

Force = 280 + (16-10/10)

Force = 280 + 0.6

Force = 280.6N

Hence the force exerted by the snowmobile to accelerate is 280.6N

see the picture for the vector

the magnitude of the vector by pythagorean theorem

r = √( (-10)^2 + (3)^2 ) = √109

magnitude = √109 units

the direction angle between vector and x-axis is

tan^(-1)(3/10) = 16.699

so the direction is approximately 16.7 degrees north of west