an object 2cm high when placed in front of a converging mirror produces a virtual image 3cm high. if the object is placed at a distance of 8cm from the pole of the mirror, calculate the position of the image

v= +12cm

Explanation:

m = (size of image)/(size of the object) = -v/u  

u = - 8 cm

 3/2 = -v/u 

3/2 = -v/-8 

v = +12 cm

Using mirror formula, 

1/v + 1/u = 1/f  ...(i)

1/12 + 1/(-8) = 1/f 

f = -24 cm

Focal length is 24 cm

whichever one it is, it's definitely not one that you included on the list you provided.

answer( sicar );