Calculate the energy of a photon of infrared light that has a frequency of 2.40 x 10^12 Hz
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According to the law of energy, it states that energy can never be created nor be destroyed. It can only transfer from one thing to another.

These are the various type of energy:-

We can obtain the energy of the photon of the infrared light by applying the following formula:

Energy (E) = Planck's constant (h) × frequency (f)  

After putting the value:-

After solving the equation, the energy is:-

E = 1.60×10¯²¹ J

Thus, the energy of the photon of the infrared light which has a frequency of 2.40×10¹² Hz is 1.60×10¯²¹J

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Option C. 1.60×10¯²¹ J

Explanation:

The following data were obtained from the question:

Frequency (f) = 2.40×10¹² Hz

Energy (E) =..?

We can obtain the energy of the photon of the infrared light by applying the following formula:

Energy (E) = Planck's constant (h) × frequency (f)

E = hf

Frequency (f) = 2.40×10¹² Hz

Planck's constant (h) = 6.63×10¯³⁴ Js

Energy (E) =..?

E = 6.63×10¯³⁴ × 2.40×10¹²

E = 1.60×10¯²¹ J

Thus, the energy of the photon of the infrared light which has a frequency of 2.40×10¹² Hz is 1.60×10¯²¹ J

indium, and thallium have three electrons i think

it is a solid

explanation: